Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] Clay 40 ft wc=37% SG=2.70

Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

Find: σ’v at d=30 feet in [lb/ft2] Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100%

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100%

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100%

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100% 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100% 20 [ft] ?

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100% 20 [ft] ?

Find: σ’v at d=30 feet in [lb/ft2] γ’clay wc=37% SG=2.70 S=100% ?

Find: σ’v at d=30 feet in [lb/ft2] γ’clay= γT - γW wc=37% SG=2.70 S=100% ?

Find: σ’v at d=30 feet in [lb/ft2] γ’clay= γT - γW wc=37% SG=2.70 S=100% ?

Find: σ’v at d=30 feet in [lb/ft2] ? γ’clay= γT - γW wc=37% SG=2.70 S=100% ?

Find: σ’v at d=30 feet in [lb/ft2] ? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

Find: σ’v at d=30 feet in [lb/ft2] ? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

Find: σ’v at d=30 feet in [lb/ft2] ? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

Find: σ’v at d=30 feet in [lb/ft2] ? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww 100 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww 100 100 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww 100 100 [lb] 37 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 37 0.37*Ws =Ww 100 100 [lb] 37 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 37 0.37*Ws =Ww 100 100 [lb] 37 [lb] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] Vw=Ww γW A W S V [ft3] W [lb] 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] Vw=Ww γW A W S V [ft3] W [lb] = 37 [lb] 62.4 [lb/ft3] 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] Vw=Ww γW A W S V [ft3] W [lb] = 37 [lb] 62.4 [lb/ft3] 37 100 = 0.593 [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] Vw=Ww γW A W S V [ft3] W [lb] = 37 [lb] 62.4 [lb/ft3] 0.593 37 100 = 0.593 [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] W S V [ft3] W [lb] 0.593 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS A W S V [ft3] W [lb] 0.593 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS A W S V [ft3] W [lb] 0.593 37 γW*SG 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 0.593 37 γW*SG 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 100 = 0.593 [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 wc=37% SG=2.70 S=100% ? γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 γT=WT VT

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 γT=WT VT 137 [lb] 1.186 [ft3] = =

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] assumed 1.186 137 γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] assumed 1.186 137 Followed from assumption γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] assumed 1.186 137 Followed from assumption γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h σv’=Σ γ’*h 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay σv’=2,062 [lb/ft2] 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 σv’=γ*h γ’clay= γT - γW σv’=Σ γ*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay σv’=2,062 [lb/ft3] 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] 1,438 1,957 C) 2,062 D) 3,310 σv’=γ*h γ’clay= γT - γW σv’=Σ γ*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γsand*hsand +γ’clay * hclay σv’=2,062 [lb/ft3] Answer  C 20 [ft]

Find: σ’v at d=30 feet in [lb/ft2] VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [lb] assumed 1.186 137 Followed from assumption γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] (1+wc)*γw wc+(1/SG) γT= γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] 0.37 62.4 [lb/ft3] (1+wc)*γw wc+(1/SG) γT= 2.70 γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

Find: σ’v at d=30 feet in [lb/ft2] 0.37 62.4 [lb/ft3] (1+wc)*γw wc+(1/SG) γT= 2.70 γT=115.5 [lb/ft3] γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

? Index σ’v = Σ γ d γT=100 [lb/ft3] +γclay dclay 1 Find: σ’v at d = 30 feet σ’v = Σ γ d d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft Clay = γsand dsand +γclay dclay Geostatic Stress problem 1. Find the effective vertical stress at a depth of 30 feet given the following figure. A 10 foot layer of sand with a total unit weight of 100 [lb/ft^3] overlays a 40 foot thick layer of clay with a water content of 37%. The ground water table exists at the sand – clay interface. The first time I saw this problem I thought, do I even have enough information to information to solve this problem. Image is not to scale. 40 ft text wc = 37% ? 20 [ft]