Find: σ’v at d=30 feet in [lb/ft2]

Παρουσίαση με θέμα: "Find: σ’v at d=30 feet in [lb/ft2]"— Μεταγράφημα παρουσίασης:

1 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] Clay 40 ft wc=37% SG=2.70

2 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

3 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

4 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

5 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70

6 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

7 Find: σ’v at d=30 feet in [lb/ft2]
Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

8 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

9 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 20 ft Clay 40 ft wc=37% SG=2.70 S=100%

10 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100%

11 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100%

12 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100%

13 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100% 20 [ft]

14 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100% 20 [ft] ?

15 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft σv’=γ’sand*hsand +γ’clay * hclay Clay 40 ft wc=37% SG=2.70 S=100% 20 [ft] ?

16 Find: σ’v at d=30 feet in [lb/ft2]
γ’clay wc=37% SG=2.70 S=100% ?

17 Find: σ’v at d=30 feet in [lb/ft2]
γ’clay= γT - γW wc=37% SG=2.70 S=100% ?

18 Find: σ’v at d=30 feet in [lb/ft2]
γ’clay= γT - γW wc=37% SG=2.70 S=100% ?

19 Find: σ’v at d=30 feet in [lb/ft2]
? γ’clay= γT - γW wc=37% SG=2.70 S=100% ?

20 Find: σ’v at d=30 feet in [lb/ft2]
? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

21 Find: σ’v at d=30 feet in [lb/ft2]
? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

22 Find: σ’v at d=30 feet in [lb/ft2]
? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

23 Find: σ’v at d=30 feet in [lb/ft2]
? γ’clay= γT - γW wc=37% SG=2.70 S=100% γT=WT VT ?

24 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

25 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

26 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

27 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

28 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

29 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

30 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

31 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww wc=37% SG=2.70 S=100% ? γT=WT VT

32 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww wc=37% SG=2.70 S=100% ? γT=WT VT

33 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww 100 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

34 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww 100 100 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

35 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 0.37*Ws =Ww 100 100 [lb] 37 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

36 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 37 0.37*Ws =Ww 100 100 [lb] 37 [lb] wc=37% SG=2.70 S=100% ? γT=WT VT

37 Find: σ’v at d=30 feet in [lb/ft2]
wc=Ww Ws A W S V [ft3] W [lb] wc*Ws =Ww 37 0.37*Ws =Ww 100 100 [lb] 37 [lb] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

38 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

39 Find: σ’v at d=30 feet in [lb/ft2]
Vw=Ww γW A W S V [ft3] W [lb] 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

40 Find: σ’v at d=30 feet in [lb/ft2]
Vw=Ww γW A W S V [ft3] W [lb] = 37 [lb] 62.4 [lb/ft3] 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

41 Find: σ’v at d=30 feet in [lb/ft2]
Vw=Ww γW A W S V [ft3] W [lb] = 37 [lb] 62.4 [lb/ft3] 37 100 = [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

42 Find: σ’v at d=30 feet in [lb/ft2]
Vw=Ww γW A W S V [ft3] W [lb] = 37 [lb] 62.4 [lb/ft3] 0.593 37 100 = [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

43 Find: σ’v at d=30 feet in [lb/ft2]
W S V [ft3] W [lb] 0.593 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

44 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS A W S V [ft3] W [lb] 0.593 37 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

45 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS A W S V [ft3] W [lb] 0.593 37 γW*SG 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

46 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 0.593 37 γW*SG 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

47 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

48 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 100 137 wc=37% SG=2.70 S=100% ? γT=WT VT

49 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 100 = 0.593 [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

50 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 137 wc=37% SG=2.70 S=100% ? γT=WT VT

51 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 wc=37% SG=2.70 S=100% ? γT=WT VT

52 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 wc=37% SG=2.70 S=100% ? γT=WT VT

53 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 γT=WT VT

54 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 γT=WT VT 137 [lb] 1.186 [ft3] = =

55 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] 1.186 137 γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

56 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] assumed 1.186 137 γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

57 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] assumed 1.186 137 Followed from assumption γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

58 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [ft3] assumed 1.186 137 Followed from assumption γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

59 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h σv’=Σ γ’*h 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

60 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

61 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

62 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] σv’=γ’sand*hsand +γ’clay * hclay ? 20 [ft]

63 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay 20 [ft]

64 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay 20 [ft]

65 Find: σ’v at d=30 feet in [lb/ft2]
σv’=γ’*h γ’clay= γT - γW σv’=Σ γ’*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay σv’=2,062 [lb/ft2] 20 [ft]

66 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 σv’=γ*h γ’clay= γT - γW σv’=Σ γ*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γ’sand*hsand +γ’clay * hclay σv’=2,062 [lb/ft3] 20 [ft]

67 Find: σ’v at d=30 feet in [lb/ft2]
1,438 1,957 C) 2,062 D) 3,310 σv’=γ*h γ’clay= γT - γW σv’=Σ γ*h 62.4 [lb/ft3] 115.5 [lb/ft3] 100 [lb/ft3] 10 [ft] γ’clay= 53.1 [lb/ft3] σv’=γsand*hsand +γ’clay * hclay σv’=2,062 [lb/ft3] Answer  C 20 [ft]

68 Find: σ’v at d=30 feet in [lb/ft2]
VS=WS γS WS γW*SG A W S V [ft3] W [lb] = 100 [lb] 62.4 [lb/ft3]*2.70 0.593 37 = 0.593 100 = 0.593 [lb] assumed 1.186 137 Followed from assumption γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

69 Find: σ’v at d=30 feet in [lb/ft2]
γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

70 Find: σ’v at d=30 feet in [lb/ft2]
(1+wc)*γw wc+(1/SG) γT= γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

71 Find: σ’v at d=30 feet in [lb/ft2]
0.37 62.4 [lb/ft3] (1+wc)*γw wc+(1/SG) γT= 2.70 γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

72 Find: σ’v at d=30 feet in [lb/ft2]
0.37 62.4 [lb/ft3] (1+wc)*γw wc+(1/SG) γT= 2.70 γT=115.5 [lb/ft3] γT=WT VT 137 [lb] 1.186 [ft3] = = 115.5 [lb/ft3]

73 ? Index σ’v = Σ γ d γT=100 [lb/ft3] +γclay dclay 1
Find: σ’v at d = 30 feet σ’v = Σ γ d d Sand 10 ft γT=100 [lb/ft3] 100 [lb/ft3] 10 [ft] 20 ft Clay = γsand dsand +γclay dclay Geostatic Stress problem 1. Find the effective vertical stress at a depth of 30 feet given the following figure. A 10 foot layer of sand with a total unit weight of 100 [lb/ft^3] overlays a 40 foot thick layer of clay with a water content of 37%. The ground water table exists at the sand – clay interface. The first time I saw this problem I thought, do I even have enough information to information to solve this problem. Image is not to scale. 40 ft text wc = 37% ? 20 [ft]