N ∆ x H = ε* ∂E/∂t.

Παρουσίαση με θέμα: "N ∆ x H = ε* ∂E/∂t."— Μεταγράφημα παρουσίασης:

1 N ∆ x H = ε* ∂E/∂t

2 N

3 N S ∆ x E = - μo ∂H/∂t

4 εo = dielectric constant or pemittivity
μo = permeability

5

6

7

8

9

10 1 μoεo = c2

11 ∆ ∆ ∆ ∆ x H = ε* ∂E/∂t x E = - μ* ∂H/∂t 2 x E = ε*μ* ∂E2/∂t2 2 x
H = ε*μ* ∂H2/∂t2

12 E = Eo e iωt-γx ν = ω/2π E = Eo e iωt-γx E = Eo e iωt

13 ∆ ∆ 2 x E = ε*μ* ∂E2/∂t2 2 x E = k ∂E2/∂t2 E = Eo e iωt Ψ = ψo e iωt
2π ν = ω p = h/ ν

14 ∆ ∆ ∆ 2 E = k ∂E2/∂t2 2 E = k ∂E2/∂t2 E = Eo e iωt
ψo ∂(e iωt )2/∂t2 = - ω2 ψo e iωt 2 ∆ Ψ = ψo e iωt = ∂2/∂x2 + ∂2/∂y2 + ∂2/∂z2 4π2ν = ω2 2π ν = ω p = h/ ν 4π2ν = ω2 p/h = ν 4π2p/h2 = ω2 p2/ħ2 = ω2

15 ∆ ∆ 2 E = k ∂E2/∂t2 E = Eo e iωt ψo ∂(e iωt )2/∂t2 = - ω2 ψo e iωt 2
= ∂2/∂x2 + ∂2/∂y2 + ∂2/∂z2

16 4π2ν = ω2 2π ν = ω p = h/ λ 4π2ν = ω2 p= hν ν = 1/ λ 4π2p/h2 = ω2 p2/ħ2 = ω2 p = hω/2π E = T + V ½ mv2 = p2/2m E = p2/2m + V p2 = 2m(E-V) ω2 = 2 ħ-2m (E-V) p = ħω p2/ħ2 = ω2 p2/ħ2 = ω2

17 ∆ ∆ ∆ ∆ ∆ E = Eo e iωt = ∂2/∂x2 + ∂2/∂y2 + ∂2/∂z2 2
ψo e iωt = - ω2 ψo e iωt Ψ = ψo e iωt 2 ∆ ψo = - ω2 ψo 2 ∆ ψo + ω2 ψo = 0 ω2 = 2 ħ-2m (E-V) 2 ∆ ψo ħ-2m (E-V) ψo = 0 2 8π2h ψo (E-V) ψo = 0 ∆ m

18 E = T + V ½ mv2 = p2/2m E = p2/2m + V p2 = 2m(E-V)

19 N

20 N S