INTERFEROMETER.

Παρουσίαση με θέμα: "INTERFEROMETER."— Μεταγράφημα παρουσίασης:

1 INTERFEROMETER

2 Fabry Pérot Interferometer
Maurice Paul Auguste Charles Fabry ( ) Alfred Pérot ( )

3 Michelson Fringes Fabry Perot Fringes

4 Fabry-Perot Interferometer
S2 S1

5 T+R+A=1 T: Transmittance (tt) R : Reflectance (r2) A: Absorbance

6 Irradiance d: successive phase difference of the transmitted rays

7 A A (q) : Airy’s function A

8 Measurement of sharpness of fringes

9 Finesse F of the mirror system is defined by

10 Chromatic Resolving power

11 Fabry-Perot Interferometer
θ o 30

12 I0

13 IR/I IT/I φ

14 Transmitted intensity

15 d/λ = 10 , f = 8 d/λ = 10 , f = 1 θ θ d/λ = 1000 , f = 7
o θ 30 θ d/λ = 1000 , f = 7 d/λ = 10 , f = 2 θ θ o 3

16 Michelson fringes Fabry-Perot fringes

17 Full width at half maximum

18 Resolved wavelengths

19 Unresolved wavelengths

20 Barely resolved

21 Chromatic resolving power of
Fabry Perot interferometer

22 Doublet separation in Fabry-Perot interferometer

23 &

24

25

26 λ1= 589.0 nm λ2= 589.6 nm Δλ= 0.6 nm λ/Δλ~1000 CRP<1000
Sodium doublet λ1= nm λ2= nm Δλ= 0.6 nm λ/Δλ~1000 CRP<1000

27 λ1= 589.0 nm λ2= 589.6 nm Δλ= 0.6 nm λ/Δλ~1000 CRP ~ 1000
Sodium doublet λ1= nm λ2= nm Δλ= 0.6 nm λ/Δλ~1000 CRP ~ 1000

28 λ1= 589.0 nm λ2= 589.6 nm Δλ= 0.6 nm λ/Δλ~1000 CRP >1000
Sodium doublet λ1= nm λ2= nm Δλ= 0.6 nm λ/Δλ~1000 CRP >1000

29 λ1= 589.0 nm λ2= 589.6 nm Δλ= 0.6 nm λ/Δλ~1000 CRP >> 1000
Sodium doublet λ1= nm λ2= nm Δλ= 0.6 nm λ/Δλ~1000 CRP >> 1000

30 λ1= 589.0 nm λ2= 589.6 nm Δλ= 0.6 nm λ/Δλ~1000 CRP>>>1000
Sodium doublet λ1= nm λ2= nm Δλ= 0.6 nm λ/Δλ~1000 CRP>>>1000