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©G Dear2008 – Not to be sold/Free to use
Area Circles & Sectors Stage 4 - Year 9 Press Ctrl-A ©G Dear2008 – Not to be sold/Free to use
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Circles A = π x r2 = π x 32 3m r = … ≈ 28.3 m2
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Area of Sector θ A = x π r2 360 55 = x π x 32 360 = 4.319 689 899
3cm 55 360 = x π x 32 55o = = 4.3 cm2
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Area of Sector θ A = x π r2 360 135 = x π x 72 360 = 57.726 765 01
7cm 135 360 = x π x 72 135o = = 57.7 cm2
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Find Radius θ A = x π r2 360 45 48 = x π x r2 360 360 r2 = x 48 45π
÷45 x360 ÷π A=48cm2 48 = x π x r2 45o 360 45π r2 = x 48 r = (360÷(45xπ)x48) = cm Hint
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Find Radius θ A = x π r2 360 120 96 = x π x r2 360 360 r2 = x96 120π
÷120 x360 ÷π 96 = x π x r2 120o 360 120π A=96cm2 r2 = x96 r = (360÷(120xπ)x96) = 9.57 cm Hint
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